Asked by JIm
How many seconds does it take to deposit 81.5 g of Zn on a steel gate when 21.0 A is passed through a ZnSO4 solution?
Answers
Answered by
DrBob222
It takes 96,485 coulombs to deposit 65.4g/2 = estimated 33 g Zn
You want 81.5 g so that will require how many coulombs?
That's 96,485 x (81.5/33) = ? C.
Then C = amperes x seconds.
You know C and amperes, solve for seconds. Remember that 33 g is an estimate so you need to use more accurate values.
You want 81.5 g so that will require how many coulombs?
That's 96,485 x (81.5/33) = ? C.
Then C = amperes x seconds.
You know C and amperes, solve for seconds. Remember that 33 g is an estimate so you need to use more accurate values.
Answered by
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