To determine how many real solutions the quadratic equation \(4x^2 + x + 3 = 0\) has, we can use the discriminant. The discriminant \(D\) of a quadratic equation in the standard form \(ax^2 + bx + c = 0\) is given by:
\[ D = b^2 - 4ac \]
For the equation \(4x^2 + x + 3 = 0\), we identify the coefficients:
- \(a = 4\)
- \(b = 1\)
- \(c = 3\)
Now we can calculate the discriminant:
\[ D = (1)^2 - 4(4)(3) = 1 - 48 = -47 \]
Since the discriminant \(D\) is negative (\(-47 < 0\)), this means that the quadratic equation has no real solutions.
Thus, the answer is:
no real solutions.