To determine the number of real solutions for the quadratic equation \(4x^2 + x + 3 = 0\), we can use the discriminant method. The discriminant \(D\) of a quadratic equation \(ax^2 + bx + c = 0\) is given by the formula:
\[ D = b^2 - 4ac \]
In our equation, the coefficients are:
- \(a = 4\)
- \(b = 1\)
- \(c = 3\)
Now, let's calculate the discriminant:
\[ D = (1)^2 - 4(4)(3) \] \[ D = 1 - 48 \] \[ D = 1 - 48 = -47 \]
Since the discriminant \(D\) is negative (\(D < 0\)), this means that the quadratic equation has no real solutions; instead, it has two complex solutions.
Thus, the answer is that the equation \(4x^2 + x + 3 = 0\) has 0 real solutions.