how many real number solutions Dows the equation have. 0=3x^2+18x+27

Answer 1

The equation 0 = 3x^2 + 18x + 27 can be simplified further by factoring out the common factor of 3 from each term:

0 = 3(x^2 + 6x + 9)

Now, we can factor the quadratic expression inside the parentheses:

0 = 3(x + 3)(x + 3)

This gives us (x + 3)(x + 3) = 0

Therefore, the equation has one real number solution, which is x = -3.