The equation 0 = 3x^2 + 18x + 27 can be simplified by dividing all terms by 3 to get:
0 = x^2 + 6x + 9
This can be further simplified to:
0 = (x + 3)^2
The equation has one real number solution, x = -3.
How many real-number solutions does the equation have?
0 equals 3 x squared plus 18 x plus 27
1 answer