This equation has no real number solutions.
To see why, we can use the discriminant of the quadratic formula:
b^2 - 4ac
For the equation 0=-5x^(2)+8x-7, a=-5, b=8, and c=-7. Substituting in these values, we get:
8^2 - 4(-5)(-7) = 8^2 - 140 = -56
Since the discriminant is negative, the quadratic equation has no real number solutions.
How many real number solutions does the equation have?
0=-5x^(2)+8x-7
1 answer