How many real number solutions does the equation have?

0=-5x^(2)+8x-7

1 answer

This equation has no real number solutions.

To see why, we can use the discriminant of the quadratic formula:

b^2 - 4ac

For the equation 0=-5x^(2)+8x-7, a=-5, b=8, and c=-7. Substituting in these values, we get:

8^2 - 4(-5)(-7) = 8^2 - 140 = -56

Since the discriminant is negative, the quadratic equation has no real number solutions.