How many real number solutions are there to the equation 0=-3x^2+x-4

A) 0*****

B) 1

C) 2

D) 3

Help on how to solve this.

2 answers

recall the discriminant of a quadratic: b^2-4ac

Here, that is 1^2-4(-3)(-4) = 1+48 = 49

since it is positive, there are 2 real roots.
Thank You!