In a dihybrid cross involving two traits, each trait is typically represented by two alleles (one from each parent). If we assume that each trait can have two different alleles (let's say A/a for the first trait and B/b for the second trait), then the possible combinations of alleles can be calculated using the formula \( 2^n \), where \( n \) is the number of traits.
For a dihybrid cross:
- There are 2 traits (A/a and B/b)
- Therefore, \( n = 2 \)
Using the formula:
\[ 2^n = 2^2 = 4 \]
The possible combinations of alleles are:
- AB
- Ab
- aB
- ab
Thus, for a dihybrid cross with two traits, there are four combinations of alleles.
The correct answer is: Four combinations.
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