From your description, the numbers can only contain 5, 6, 7, 8 and/or 9.
You can start with 666, 678 and go to 996.
How many positive three-digit integers with each digit greater than 4 are divisible by 6??
4 answers
from the question the only solutions to this would be with only three of the same numbers are 666,888. Then with two of the same numbers with no particular order will be 966,558,588,996. Then the ones with 3 different numbers would be 678 and 798. 666 and 888 can only be used once in the same format so it'll be 2. Then 966,558,588,996 can only be used once so it'll be 6 then. Finally 678 can be 678,876,786,and 768 and 798 can be 798 or 978. So it'll be twelve
12 is wrong
It is 16. Just list all the cases
2 answers