How many PCR cycles are sufficient to create over a billion copies of your target fragment?

1 answer

The number of PCR cycles needed to generate over a billion copies of a target fragment can be estimated using the formula for exponential amplification:

\[ N = N_0 \times 2^n \]

where:

  • \( N \) is the final number of copies,
  • \( N_0 \) is the initial number of copies (usually 1 if starting with a single template),
  • \( n \) is the number of PCR cycles.

If we want to produce over a billion copies (\( N > 10^9 \)) and start with 1 copy (\( N_0 = 1 \)), we can set up the equation as follows:

\[ 1 \times 2^n > 10^9 \]

Taking the logarithm base 2 of both sides gives:

\[ n > \log_2(10^9) \]

Calculating this:

  1. \( \log_2(10) \approx 3.32 \)
  2. Therefore, \( \log_2(10^9) \approx 9 \times 3.32 = 29.88 \)

So, rounding up, at least 30 cycles are required to exceed a billion copies, assuming 100% efficiency in each cycle. In practice, however, PCR is not 100% efficient, and efficiency can decrease with more cycles due to factors like reagent depletion and the formation of non-specific products. Thus, most protocols suggest using between 30 to 35 cycles to reliably achieve a billion copies, taking into account possible inefficiencies.