how many P2O5 molecules are contained 55.3g of P2O2

Answer 1

To determine how many P2O5 molecules are contained in 55.3g of P2O2, we first need to calculate the number of moles of P2O2 present in 55.3g.

The molar mass of P2O2 is:
P = 30.97 g/mol
O = 16.00 g/mol

Molar mass of P2O2 = 2 * (30.97) + 2 * (16.00) = 60.94 g/mol

Number of moles of P2O2 = Mass / Molar mass
Number of moles = 55.3g / 60.94 g/mol ≈ 0.907 moles

Since one molecule of P2O2 contains 2 oxygen atoms, the number of moles of oxygen atoms is 0.907 * 2 = 1.814 moles.

Now, we convert the moles of oxygen atoms to moles of P2O5. In each molecule of P2O5, there are 5 oxygen atoms.

1.814 moles * (1 mol P2O5 / 5 mol O) = 0.363 moles of P2O5

Finally, we convert moles of P2O5 to molecules:

0.363 moles * 6.02 x10^23 molecules/mol = 2.18 x 10^23 molecules of P2O5

Therefore, there are approximately 2.18 x 10^23 molecules of P2O5 in 55.3g of P2O2.