How many mols of dinitrogen monoxide are contained in 56.0L at STP?
2 answers
56.0L x (1 mol/22.4L) = ? mols.
It is 2.50 moles if you are using significant digits!
56.0 L • 1 mol /22.4 L = 2.50 mol
56.0 L • 1 mol /22.4 L = 2.50 mol
1 answer