How many moles of water vapour are formed when 10L of butane gas C4H10is burned in oxygen at STP

Question

DrBob222 · Accepted Answer

2C4H10 + 13O2 ==> 8CO2 + 10H2O 10 L C4H10 @ STP will produce 10L x 10/2 = 50 L H2O @ STP. 1 mol H2O will occupy 22.4 L. So how many mols are in 50 L? Post your work if you get stuck.

Nuhamin · Answer

2c4h10+13o2

Muradi · Answer

Thank you I am very happy to get this answer

mintesinot · Answer

1mole of any gas equals the volume 22.4l. so 1mole=22.4l x =50l use chirs cross method and x=2.2mol