How many moles of tungsten atoms are there in 4.3x10 exponent 26, atoms of tungsten?

Answer 1

To determine the number of moles of tungsten atoms in 4.3x10^26 atoms of tungsten, we need to use Avogadro's number. Avogadro's number is 6.022x10^23 atoms per mole.

First, we divide the given number of tungsten atoms by Avogadro's number to find the number of moles:

4.3x10^26 atoms / 6.022x10^23 atoms/mol = 71.3 moles

Therefore, there are 71.3 moles of tungsten atoms in 4.3x10^26 atoms of tungsten.