How many moles of sodium acetate CH3COONA must be dissolved in 1.00L of 0.200M acetic acid to make a buffer pH 4.56? ka of acetic acid is 1.76x10^-
2 answers
Use the Henderson-Hasselbalch equation.
PH= 4.56, PKa= 4.74
PH = pka +log(Base/Acid)
-0.18 = log(Base/0.200)
B = 0.1321 M >>>> o.1321 mol/L
Molocular weight of acetic acid = 82.03 g
(0.1321 mol/L)(0.4 l) 0.05284 mol
(0.05284 mol)(82.03 g/ mol) = 4.33 g.
I hope this helps!
PH = pka +log(Base/Acid)
-0.18 = log(Base/0.200)
B = 0.1321 M >>>> o.1321 mol/L
Molocular weight of acetic acid = 82.03 g
(0.1321 mol/L)(0.4 l) 0.05284 mol
(0.05284 mol)(82.03 g/ mol) = 4.33 g.
I hope this helps!
2 answers