I don't know but if all of the Ag in AgNO3 is converted to Ag2CrO4, then
1 mol 2AgNO3 = 1 mol Ag2CrO4; therefore, 1 mol AgNO3 will produce 1/2 mol Ag2CrO4. You have mols AgNO3 = 146/molar mass AgNO3 = approx 0.86 but that's an estimate.
Then 0.86 mols AgNO3 = 0.43 mols Ag2CrO4.
You need to redo all of the steps and get accuate numbers.
How many moles of silver chromate will be produced from 146 g of silver nitrate?
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