How many moles of silicon dioxide SiO2 are needed to produce 13.5 moles of water?

SiO2 + 4 HF  SiF4 + 2 H2O
Responses

322 mol
322 mol

88.75 mol
88.75 mol

6.75 mol
6.75 mol

0.3 mol
0.3 mol

1 answer

To determine how many moles of silicon dioxide (SiO2) are needed to produce 13.5 moles of water (H2O), we can refer to the balanced chemical equation:

\[ \text{SiO}_2 + 4 \text{HF} \rightarrow \text{SiF}_4 + 2 \text{H}_2\text{O} \]

From the balanced equation, we see that 1 mole of SiO2 produces 2 moles of H2O.

To find out how many moles of SiO2 are required to produce 13.5 moles of H2O, we can set up the proportion:

\[ 1 \text{ mol SiO}_2 \text{ produces } 2 \text{ mol H}_2\text{O} \]

We need to find \( x \) moles of SiO2 to produce 13.5 moles of H2O.

Using the ratio from the balanced equation:

\[ x \text{ mol SiO}_2 = \frac{13.5 \text{ mol H}_2\text{O}}{2} \]

Calculating this gives:

\[ x = \frac{13.5}{2} = 6.75 \text{ mol SiO}_2 \]

Therefore, 6.75 moles of silicon dioxide (SiO2) are needed to produce 13.5 moles of water (H2O).

The correct response is 6.75 mol.