How many moles of oxygen gas must be in a 12.2 L container to exert a pressure of 0.877 atm at a temperature of 35.0°C (the ideal gas constant in this case is 0.0821 L atm / mole K)?

Question

How many moles of oxygen gas must be in a 12.2 L container to exert a pressure of 0.877 atm at a temperature of 35.0°C (the ideal gas constant in this case is  0.0821 L atm / mole K)?
Please show work

DrBob222 · Answer

Your old friend PV = nRT That's the ideal gas law equation. Memorize that.

Veronica · Answer

@DrBob222 so how would I write out the equation?

DrBob222 · Answer

It's PV = nRT P = 0.877 atm V = 12.2 L n = ? R = 0.0821 L*atm/mol*K T = 273.15 + 35 = ? Solve for n

Veronica · Answer

so its 0.57?

DrBob222 · Answer

No, I don't get 0.57. PV = nRT n = PV/RT n = 0.877*12.2/0.0821*308