1 mole contains 6.02E23; therefore,
mol = 6.56E22/6.02E23 = ?
There are 1.79 x 6.02E23 molecules of NO in l.79 moles and 2 x that number for the numb er of atoms.
How many MOLES of oxygen are present in 6.56E+22 molecules of nitrogen monoxide
How many ATOMS of nitrogen are present in 1.79 moles of nitrogen monoxide ?
1 answer