Number of moles =Molarity x volume in litres
The overall raction is
C2O4^2-(aq) + MnO4^-(aq) + H^+(aq) + -->
Mn^2+(aq) + CO2(g) + H2O(l)
which you need to balance to find the number of moles of KMnO4
reuse
number of moles = molarity x volume (in litres)
to find the molarity of the KMnO4 solution
how many moles of Na2C2O4 are there in 25.00 mL of a .7654 M solution of sodium oxalate?
How many moles of KMn)4 are required to reach with the moles of Na2C2O4 in the last problem?
and also,
if the KmnO4 of the last problem is in 30.30mL of solution what is the molarity (M) of the KmnO4 solution?
1 answer
1 answer