figure the H+ concentration of each
1) H+ =10^-9.75=1.7782794e-10
2) H=10^-9.01=9.7723722e-10
so the difference between these two concentrations is 7.9940928e-10
How many moles of H3O+ or OH-
must you add per liter of HA solution to adjust its pH from 9.75 to 9.01? Assume a negligible volume change.
……….x 10………Moles of ……………………..h3O+ or
OH-
I got 4.6001 x 10-5 M of h3o+...but it was wrong
2 answers
Check this out.
pH = 9.75 gives (H^+) = 1.77E-10 mols/L
pH = 9.01 gives (H^+) = 9.77E-10 mols/L.
Difference is 8.00E-10 so you want to increase the (H3O^+) by 8.00E-10 mols/L. Do you see anything wrong with that?
pH = 9.75 gives (H^+) = 1.77E-10 mols/L
pH = 9.01 gives (H^+) = 9.77E-10 mols/L.
Difference is 8.00E-10 so you want to increase the (H3O^+) by 8.00E-10 mols/L. Do you see anything wrong with that?
1 answer