46.9 psi = 3.19 atmospheres.
Then use PV = nRT and solve for n
How many moles of gas must be forced into a 4.4 L tire to give it a gauge pressure of 32.4 psi at 30 ∘C? The gauge pressure is relative to atmospheric pressure. Assume that atmospheric pressure is 14.5 psi so that the total pressure in the tire is 46.9 psi .
2 answers
A mixture of helium, nitrogen, and oxygen has a total pressure of 763 mmHg . The partial pressures of helium and nitrogen are 244 mmHg and 190 mmHg , respectively.
What is the partial pressure of oxygen in the mixture?
What is the partial pressure of oxygen in the mixture?
2 answers