How many moles of gas are in a 4.20 L container at 310 K and 0.36 atm? Given R= 0.0821 L atm/ mol K.





Use the sample problem below and follow the 5 steps to help you solve the problem you were given.

a
38.4 moles
b
16.9 moles
c
0.004 moles
d
0.06 moles

1 answer

To solve this problem, we can use the ideal gas law equation:

PV = nRT

Where:
P = pressure in atm
V = volume in liters
n = number of moles
R = ideal gas constant (0.0821 L atm/ mol K)
T = temperature in Kelvin

We can rearrange the equation to solve for the number of moles:

n = PV / RT

Substituting the given values:

P = 0.36 atm
V = 4.20 L
R = 0.0821 L atm/ mol K
T = 310 K

n = (0.36 atm x 4.20 L) / (0.0821 L atm/ mol K x 310 K)

n ≈ 0.017 moles

Therefore, the correct answer is c) 0.004 moles.