How many moles of Fe(N03)3 are needed to react with 0.549 mol of NA2S

Answer 1

The balanced chemical equation for the reaction between Fe(NO3)3 and Na2S is:

Fe(NO3)3 + 3Na2S -> Fe2(SO4)3 + 6NaNO3

From the equation, we see that 1 mole of Fe(NO3)3 reacts with 3 moles of Na2S.

Therefore, in order to react with 0.549 mol of Na2S, we need:

0.549 mol Na2S * (1 mol Fe(NO3)3 / 3 mol Na2S) = 0.183 mol Fe(NO3)3

So, 0.183 moles of Fe(NO3)3 are needed to react with 0.549 mol of Na2S.