How many moles of chlorate ions, zinc ions, and oxygen atoms are present in 0.433 mol of zinc chlorate?
2 answers
See your post on Al2(CO3)3 to see how to do this one.
Znclo3>>>> zn^+2 +clo3^-1
Zn ions :znclo3
1 : 1
O.43moles : 0.433moles
Znclo3 :clo3 ions
1 : 1
0.433moles : 0.433 moles
Moles of znclo3 = (6.023*10^23)(0.433)
=2.607959 *10^23 molecules/atoms
Oxygen atoms in znclo3= 3*(2.607959*10^23)
=7.823877*10^23 atoms
Zn ions :znclo3
1 : 1
O.43moles : 0.433moles
Znclo3 :clo3 ions
1 : 1
0.433moles : 0.433 moles
Moles of znclo3 = (6.023*10^23)(0.433)
=2.607959 *10^23 molecules/atoms
Oxygen atoms in znclo3= 3*(2.607959*10^23)
=7.823877*10^23 atoms