Looks like the equation ought to be
Fe2O3 + C -> Fe + CO2
Now, we have 3 oxygens and we need 6:
2Fe2O3 + C -> 2Fe + 3CO2
Now we need to balance the carbons:
2Fe2O3 + 3C -> 2Fe + 3CO2
Looks like 3 moles of C for 2 moles of Fe2O3. Just figure out how many moles you have and multiply by 3/2.
How many moles of carbon are needed to react with 525 g of hematite
2FeO3+6C->4Fe+3Co2
idk how to convert moles of fe2o3 to carbon
2 answers
Oops.
2Fe2O3 + 3C -> 4Fe + 3CO2
2Fe2O3 + 3C -> 4Fe + 3CO2