To calculate the number of moles of CaO needed to react with water to produce 370g of calcium hydroxide, we first need to write and balance the chemical equation for the reaction:
CaO + H2O -> Ca(OH)2
From the balanced equation, we can see that 1 mole of CaO reacts with 1 mole of water to produce 1 mole of calcium hydroxide.
Next, we calculate the molar mass of Ca(OH)2:
Ca = 40.08 g/mol
O = 16.00 g/mol
H = 1.01 g/mol
Molar mass of Ca(OH)2 = 40.08 + 2(16.00) + 2(1.01) = 74.10 g/mol
Now we can convert the given mass of calcium hydroxide to moles using the molar mass:
370g / 74.10 g/mol = 5 moles
Since the reaction stoichiometry is 1:1:1 for CaO:H2O:Ca(OH)2, we need 5 moles of CaO to produce 5 moles of Ca(OH)2.
Therefore, 5 moles of CaO are needed to react with excess water to produce 370g of calcium hydroxide.
How many moles of CaO are needed to react with excess water to produce 370g of calcium hydroxide?
1 answer