How many moles of Cag(PO4)2 are in 1.00 g of Ca(POA)2?

(Use whole molar masses from periodic table and choose closest calculated answer)

3 answers

The molar mass of Ca(PO4)2 is:

Ca: 1 x 40.08 g/mol = 40.08 g/mol
P: 2 x 30.97 g/mol = 61.94 g/mol
O: 8 x 15.99 g/mol = 127.92 g/mol

Total: 229.94 g/mol

To find the number of moles in 1.00 g, we can use the formula:

moles = mass / molar mass

moles = 1.00 g / 229.94 g/mol

moles ≈ 0.00435

Therefore, there are approximately 0.00435 moles of Ca(PO4)2 in 1.00 g.
Which of the following compounds has dipole-dipole intermolecular forces?
All polar molecules have dipole-dipole intermolecular forces.

A polar molecule is one that has a permanent dipole moment or a separation of positive and negative charges within the molecule due to differences in electronegativity between atoms.

Therefore, any compound that has a polar bond or an asymmetrical molecular shape will have dipole-dipole intermolecular forces.

Examples of polar compounds that have dipole-dipole intermolecular forces include:

- HCl
- NH3
- CH3Cl
- CH2O

On the other hand, nonpolar compounds such as diatomic molecules (H2, N2, O2, etc.), noble gases, and symmetrical molecules like CO2, have only weak London dispersion forces as their intermolecular force.