How many moles of CaCO3 are present in 30.6g of it ?
2 answers
mols = grams/molar mass.
You have to determine the molar mass of CaCO3, by getting the molar mass of Ca and the molar mass of C, and the molar mass of O multiplied by 3 (since there are 3 oxygen atoms).
You would get 100.087 g/mol.
You would then do the mass/molar mass.
30.6/100.87 = your answer
You would get 100.087 g/mol.
You would then do the mass/molar mass.
30.6/100.87 = your answer