This is a limiting reagent (LR) problem and you know that because amounts for BOTH reactants are given. I work these the long way.
BaCl2 + MgSO4 ==> MgCl2 + BaSO4
mols BaCl2 = M x L = ?
mols MgSO4 = M x L = ?
Use the coefficients in the balanced equation to convert mols BaCl2 to mols BaSO4.
Do the same and convert mols MgSO4 to mols BaSO4.
It is likely that the two values will not be the same which means one of them is wrong; the correct value in LR problems is ALWAYS the smaller value and the reagent responsible for that is the LR.
Use the smaller value for mols BaSO4 and convert to grams.
grams BaSO4 = mols BaSO4 x molar mass BaSO4.
how many moles of BaSO4 will form if 20.0 ml of 0.600 M BaC2 is mixed with 30.0 ml of 0.500 M MgSO4?
Molarity = number of moles / litres
2 answers
thank you!