how many moles of anhydrous MgSO4 are in 2.04grams of MgSO4
2 answers
moles= massingrams/molmassMgSO4
mass: 2.04
molar mass of MgSO4: 24.3+32.1+16*4=120.4
moles= 2.04/120.4
= 0.0169mol
molar mass of MgSO4: 24.3+32.1+16*4=120.4
moles= 2.04/120.4
= 0.0169mol