from the equation, 2 moles of AL are need for each 3 moles Fe.
So, 2/3 * 1.2 = 0.8 moles of Al react with 1.2 moles Fe
how many moles of aluminum are needed to react completly with 1.2 mol of FeO
2Al(s)+3FeO(s)=3Fe(s)+ Al2O3(s)
2 answers
fam
1 answer