The balanced chemical equation for the formation of aluminum oxide is:
4Al + 3O2 -> 2Al2O3.
From the equation, we can see that 4 moles of aluminum react to form 2 moles of aluminum oxide.
Therefore, if we have 0.018531215 moles of aluminum, we can calculate the moles of aluminum oxide as follows:
0.018531215 moles Al * (2 moles Al2O3 / 4 moles Al) = 0.0092656075 moles Al2O3.
So, based on 0.018531215 moles of aluminum, 0.0092656075 moles of aluminum oxide would form.
how many moles of aluminium oxide would form based on 0.018531215 moles of aluminium
1 answer