6molAgNO3*molAg2CrO4/molAgNO3=molAg2CrO4
You need to use coefficients from chemical equation, you didn't give one, and plug coefficients into mol ration : mol/mol
How many moles of Ag2CrO4 will be produced from 6 moles of AgNO3?
2 answers
Anonymous points out that you don't have an equation; however you can use an ionic equation of
2Ag+ + CrO4^2- ==> Ag2CrO4
Assuming you have enough chromate to use all of the AgNO3, you can produce 6 mols AgNO3 x (1 mol Ag2CrO4/2 mols AgNO3) = ?
2AgNO3 + Na2CrO4 ==> Ag2CrO4 + 2NaNO3
2Ag+ + CrO4^2- ==> Ag2CrO4
Assuming you have enough chromate to use all of the AgNO3, you can produce 6 mols AgNO3 x (1 mol Ag2CrO4/2 mols AgNO3) = ?
2AgNO3 + Na2CrO4 ==> Ag2CrO4 + 2NaNO3