How many moles are in 41.8 g of dinitrogen oxide?

Express your answer with the appropriate units.

1 answer

To determine the number of moles in 41.8 g of dinitrogen oxide, we need to use its molar mass.

Dinitrogen oxide (N2O) consists of 2 nitrogen atoms (N) and 1 oxygen atom (O). The atomic masses of nitrogen and oxygen are approximately 14 g/mol and 16 g/mol, respectively.

Therefore, the molar mass of dinitrogen oxide (N2O) = (2 × 14 g/mol) + (1 × 16 g/mol) = 44 g/mol

Now, we can use the molar mass to calculate the number of moles:

Number of moles = Mass (g) / Molar mass (g/mol)
Number of moles = 41.8 g / 44 g/mol ≈ 0.950 moles

Hence, there are approximately 0.950 moles in 41.8 g of dinitrogen oxide.