For lithium bromide (LiBr):
Molar mass of LiBr = 6.94 g/mol (for Li) + 79.90 g/mol (for Br) = 86.84 g/mol
30.0 g LiBr × (1 mol LiBr / 86.84 g LiBr) = 0.346 mol LiBr
Therefore, there are 0.346 moles of lithium bromide in 30.0 g of LiBr.
For aspirin (C9H8O4):
Molar mass of C9H8O4 = 9(12.01 g/mol) + 8(1.01 g/mol) + 4(16.00 g/mol) = 180.16 g/mol
23.8 g C9H8O4 × (1 mol C9H8O4 / 180.16 g C9H8O4) = 0.132 mol C9H8O4
Therefore, there are 0.132 moles of aspirin in 23.8 g of C9H8O4.
How many moles are contained in each of the following? Be sure each of your answer entries has the correct number of significant figures.
30.0 g of lithium bromide (LiBr)
30.0 g LiBr =
mol LiBr
×
Part 2 of 2
23.8 g of aspirin (C9HgO4)
23.8 g C9H8O4=
mol CoH84
1 answer