100 g KI = 100. g / 166 g/mol = 0.602 moles KI
13.0 g C6H12O6 = 13.0 g / 180.16 g/mol = 0.0721 moles C6H12O6
How many moles are contained in each of the following? Be sure each of your answer entries has the correct number of significant figures.
100.g of potassium Iodide (KI)
100. g KI=
13.0 g of glucose (C6H12O6)
13.0g C6H12O6=
1 answer