The first step is to calculate the number of moles of silicon dioxide present in 180.3 grams:
Number of moles = Mass / Molar mass
Number of moles = 180.3 g / 60.1 g/mol
Number of moles = 3 moles
Next, we use Avogadro's number to convert moles to molecules:
1 mole of a substance = 6.022 x 10^23 particles
Number of molecules = Number of moles x Avogadro's number
Number of molecules = 3 moles x 6.022 x 10^23 molecules/mole
Number of molecules = 1.81 ×10^24 molecules
Therefore, there are 1.81 ×10^24 molecules of silicon dioxide in 180.3 grams. The answer is b) 1.81 ×10^24 molecules.
How many molecules of silicon dioxide (SiO2) are there in 180.3 grams of silicon dioxide? The molar mass of SiO2 is 60.1 g/mol. If you are unsure how to convert grams to particles, please see the example problem linked HERE. a 3.62 ×1025 molecules b 1.81 ×1024 molecules c 2.01 ×1023 molecules d 1.10 ×1026 molecules
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