How many molecules are there in 985 mL of nitrogen at 0.0 degrees C and 1.00x10^-6 mmHg?
3.50 molecules
8 answers
The digits are close but the 10^? is missing.
3.50x10^23 molecules
I don't like that answer either. Post your work and let me find the error.
By the way, the 12 atm to 25 atm problem below is OK but the site will not let me post an OK.
By the way, the 12 atm to 25 atm problem below is OK but the site will not let me post an OK.
This is my work:
985mLN / 1000 = .985 L
0.0 degrees C + 273 = 273 K
1.00x10^-6 mmHg / 760 mmHg = 1.32 atm
1.32 atm x .985 L = n ( .08206 Latm / molK)x273K
n = .0580 moles x 6.022x10^23 = 3.50 x 10^23 molecules.
Ok thanks
985mLN / 1000 = .985 L
0.0 degrees C + 273 = 273 K
1.00x10^-6 mmHg / 760 mmHg = 1.32 atm
1.32 atm x .985 L = n ( .08206 Latm / molK)x273K
n = .0580 moles x 6.022x10^23 = 3.50 x 10^23 molecules.
Ok thanks
985mLN / 1000 = .985 L
0.0 degrees C + 273 = 273 K
1.00x10^-6 mmHg / 760 mmHg = 1.32 atm YOU forgot the 10^-6
1.32 atm x .985 L = n ( .08206 Latm / molK)x273K
n = .0580 moles x 6.022x10^23 = 3.50 x 10^23 molecules.
For digits I obtained 3.48; the difference is that you rounded the 1.315 to 1.32 while I left all of that in the calculator and made all of it as one calculation. It appears you made three calculations.
0.0 degrees C + 273 = 273 K
1.00x10^-6 mmHg / 760 mmHg = 1.32 atm YOU forgot the 10^-6
1.32 atm x .985 L = n ( .08206 Latm / molK)x273K
n = .0580 moles x 6.022x10^23 = 3.50 x 10^23 molecules.
For digits I obtained 3.48; the difference is that you rounded the 1.315 to 1.32 while I left all of that in the calculator and made all of it as one calculation. It appears you made three calculations.
Also 1.00/760 is not 1.32 but 1.32E-3.
Thus 1E-6/760 = 1.32E-9 I think.
Thus 1E-6/760 = 1.32E-9 I think.
Ok thanks!
How many molecules are there in 985 mL of nitrogen at 17.0° C and1.00 x 10^-6 mm Hg?