Use the dilution formula. It is
mL1 x M1 = mL2 x M2
mL1 x 0.00673 = 50.00 x 0.000415
Solve for mL1, place that amount of the o.00673 into a 250.00 volumetric flask, add some distilled water, mix somewhat, make the mark with distilled water, stopper, mix thoroughly, label. done. Post your work if you get stuck
How many mL of a 6.73 x 10^-3 M glucose stock solution would you need to
prepare 50.00 mL of 4.15 x 10^-4 M glucose dilute solution?
1 answer
1 answer