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How many mL of 5.5 M KOH are needed to prepare 300 mL of 0.2 M KOH?
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The dilution formula is
c1v1 = c2v2
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Explain how you would prepare these solutions from powdered reagents and whatever glassware you needed:
a. 2.0 L of 1.5 M KOH the
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Can someone please check my work?
Calculate the mass of (NH4)2S2O8 needed to prepare 250mL of a 0.100M solution. I got 5.705 g.
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