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How many mL of 0.6 M H2SO4 solution are needed to react completely with 23.62 g of Fe2O3 in the following reaction?

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Fe2O3 + 3H2SO4 → 2Fe2(SO4)3 + 3H2O

The molar mass of Fe2O3 is 159.69 g/mol.

23.62 g Fe2O3 x (1 mol Fe2O3/159.69 g Fe2O3) x (3 mol H2SO4/1 mol Fe2O3) x (0.6 L H2SO4/1 mol H2SO4) = 0.735 L H2SO4 = 735 mL H2SO4

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