How many mL of 0.100M HCl are needed to neutralize 49.0mL of 0.104M Ba(OH)2 solution?

Answer 1

Ba(OH)2 + 2HCl ==> 2H2O + BaCl2

mols Ba(OH)2 = M x L = ?
Convert mols Ba(OH)2 to mols HCl using the coefficients in the balanced equation. mols HCl = twice mols Ba(OH)2.
M HCl = mols HCl/L HCl.
Solve for L and convert to mL.