2H2O ==> 2H2 + O2
10.0 L O2 at STP = 10/22.4 mols = 0.446 mols or 0.446 x 32 = 14,3 grams O2.
96,485 coulombs will produce 32/4 = 8 g O2 so
coulombs needed = 96,485 x (14.3/8) = ?
Coulombs = amperes x seconds = 1.3*seconds. Plug in coulombs and A and solve for seconds. Convert to minutes. Post your work if you get stuck.
How many minutes does it take to produce 10.0L of oxygen gas (at standard conditions)
by electrolyzing neutral water with a current of 1.3 A? What is the corresponding volume
of hydrogen gas produced?
thanks so much
1 answer