How many milliliters of an aqueous solution of 0.165 M aluminum chloride is needed to obtain 13.2 grams of the salt?

Answer 1

Convert 13.2 g AlCl3 to mols. mols = grams/molar mass = ?

Then M = mols/L solution. You know mols and M, solve for L and convert to mL.

Answer 2

599,9 mL