How many milliliters of a 0.3 molar HCl

solution are needed to react completely with
8 grams of zinc according to the following
equation?
? HCl + ? Zn → ? ZnCl2 + ? H2
Answer in units of mL

5 answers

First, you need to balance the equation. Can you do that?

You will need two moles of HCl per mole of zinc.

Ask yourself this question:
How many moles of zinc is 8 grams?
I balanced it and got:

2HCL + Zn ---> ZnCl2 + H2

And then to find moles I did: 8/65.37 and got 0.1124 moles.

But now I'm stuck, what do I do next?
You are doing fine so far.

You need 2*0.1124 = 0.2248 moles of HCl.

One liter of the solution contains 0.3 moles of HCl.

You need a bit less than a liter of the acid solution.
Okay, so would I divide 0.3 by 0.2248? >_> I'm sorry, my chemistry is my weakest subject. :(
No, you need less than a liter.