mols HCl = M x L = ?
mols NaOH = mols HCl
M NaOH = mols NaOH/L NaOH. You know mols and M, solve for L and convert to mL.
How many milliliters of a 0.100 M NaOH solution are required to neutralize 25.0 milliliters of 0.150 M HCl?
Select one:
a. 25.0 ml
b. 37.5 ml
c. 125 ml
d. 167 ml
4 answers
m(1) * v(1) = m(2) * v(2)
125ml
37.5 ml
the formula for all of these types of questions in Chemistry is: M(1)*V(1) = M(2)*V(2)
So...
0.100M*V(1) = 0.150M*25.0ml
V(1) = (0.150M*25.0ml)/0.100M
V(1) = 37.5
You can use M(1)*V(1) = M(2)*V(2) for all your questions in neutralization. It will always work.
the formula for all of these types of questions in Chemistry is: M(1)*V(1) = M(2)*V(2)
So...
0.100M*V(1) = 0.150M*25.0ml
V(1) = (0.150M*25.0ml)/0.100M
V(1) = 37.5
You can use M(1)*V(1) = M(2)*V(2) for all your questions in neutralization. It will always work.