How many milliliters of 3.60 {\rm M} {\rm HCl} are required to react with 140 {\rm mL} of 1.60 {\rm M}{\rm Al}({\rm OH})_{3}?

Answer 1

I don't understand your hieroglyphics but here is the answer.
3HCl + Al(OH)3 ==> 3H2O + AlCl3
moles Al(OH)3 = M x L = ??
Using the coefficients in the balanced equation, convert moles Al(OH)3 to moles HCl. That will be 3*moles Al(OH)3 = moles HCl.
Then M HCl = moles HCl/L HCl and convert to mL.

Answer 2

What is the mass, in kilograms, of the air in a room that measures 14.0 \times\; 14.0 \times\; 8.0 {\rm{ft}}?