BaCl2 + Na2SO4 (note my correction) ==> BaSO4 + 2NaCl
moles Na2SO4 = M x L = ??
Using the coefficients in the balanced equation, convert moles Na2SO4 to moles BaCl2. (Since the ratio is 1:1 this shouldn't be a problem.)
Now, use M BaCl2= moles BaCl2/LBaCl2 and solve for L BaCl2, then convert to mL.
For mass BaSO4, g = moles x molar mass.
How many milliliters of 0.310 M BaCl2 are needed to react completely with 60.0 mL of 0.140 M NaSO4?
1 answer