NiCl2 + 2NaOH ==> Ni(OH)2 + 2NaCl
mols NiCl2 = M x L = ?
Using the coefficients in the balanced equation, convert mols NiCl2 to mols NaOH.
Then M NaOH = mols NaOH/L NaOH. You know M and molsk solve for L NaOH and convert to mL.
How many milliliters of 0.200M NaOHsolution are needed to react with 44.0 mL of a 0.300 M NiCl2 solution?
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